Elements of Section – A1000
Area of Section0.305 in2 (2.0 cm2)
 Axis 1-1Axis 2-2
Moment of Inertia (I)0.061 in4 (2.5 cm4)0.078 in4 (3.2 cm4)
Section Modulus (S)0.086 in3 (1.4 cm3)0.125 in3 (2.0 cm3)
Radius of Gyration (r)0.447 in (1.1 cm )0.506 in (1.3 cm )
      Column Loading – A1000Unbraced
Height
(in)Allowable
Load at
Slot Face
(lbs)Max Column Load
Applied at C.G.K=0.65
(lbs)K=0.80
(lbs)K=1.0
(lbs)K=1.2
(lbs)181,9605,9005,4304,8004,210241,8405,2104,5903,8503,220361,5003,9403,2202,4802,010481,2202,9502,3001,7901,460601,0202,2601,7901,4001,130728801,8401,4601,130910847801,5501,230940*966901,3401,050**1086201,170910***KL/r > 200
       
Beam Loading – A1000
Span
(in)
Max
Allowable
Uniform
Load
(lbs)
Defl at
Uniform
load
(in)
Uniform Loading
at Deflection
Lateral
Bracing
Reduction
Factor
Span
/180
(lbs)
Span
/240
(lbs)
Span
/360
(lbs)
189600.049609609601.00
247200.077207206600.95
364800.164804403000.86
483600.293302501700.78
602900.452101601100.72
722400.65150110700.67
842100.9011080500.63
961801.168060400.59
1081601.467050300.55
1201401.755040300.52
 

Notes:

  1. Above loads include the weight of the member. This weight must be deducted to arrive at the net allowable load the beam will support.
  2. Long span beams should be supported so as to prevent rotation and twist.
  3. Allowable uniformly distributed loads are listed for various simple spans, that is, a beam on two supports. If load is concentrated at the center of the span, multiply load from the table by 0.5 and corresponding deflection by 0.8.
  4. The lateral bracing factor should be multiplied by the load to determine the load retained based on the distance between lateral braces.
Part No.FinishLengthWeightBox Qty.
A1000GR10104.00500
A1000GR20104.001000
A1000PG10104.00500
A1000PG20104.001000
A1000HG10110.20500
A1000HG20110.201000
A1000PL20104.001000
A1000PL10104.00500
A1000EA1042.00500
A1000EA2042.001000
A1000SS20110.001000
A1000SS10110.00500